Sigh.
Found another problem in the test.
Qestion E7D07
Link to schematic diagram:
http://hamexam.org/popup_image/16982If I had to honestly answer this question the purpose of C2 is to blow up transistor Q1 in the event of the input power supply being shorted. Yes, someone designed a self destruct circuit.
There are problems with the values and the answer supplied.
C2 doesn't bypass hum around D1, that was the "correct answer"
If the input is 25V and the output of the regulator is 12V as shown, then the zener needs to be 12.6V to take into account the Vbe of Q1.
If hum came in from the 25V source it would be a minor fluctuation and that circuit if R1 was suitably chosen should work down to about 15V. IOW, you could have 10 Volts of hum and that circuit would regulate it pretty well.
The problem is the value of C2. Its 4000uF.
No one that is sane uses a 4000uf capacitor in parallel with a zener unless its used to bleed off voltage on a slow charge circuit to prevent a cap exploding due to over voltage. Pretty rare to need that though I have used such a technique once or twice in the last 30 years. Certainly not its purpose here.
What happens is that C2 will charge to the value of D1, about 12.6 Volts.
Now, if Vin drops below about 13Volts such that Vin +Vce < VZener then C2 will start discharging through the base of Q1 and splits into two currents, one flowing from B to C, the other flowing from B to E.
The latter is usually no problem since its almost guaranteed to be relatively low for Q1.
The former however has no such guarantees. So if I disconnect the 25V rail for example and short it out, two things happen.
1) C1 discharges quickly causing a spark. This is relatively harmless unless you're in an explosive controlled environment.
2) C2 discharges through Q1 causing a massive current to flow through the base of Q1 blowing it.
To fix the issues, one can add a forward biased diode inline with the collector of Q1. This prevents back flow from C2 into the feed voltage. Then what you have done is create a circuit where you can detect that the input voltage has failed and yet provide a small time when energy is still available to the following stages. Realistically however this is a waste in this case since C2 would be better placed from C of Q1 to ground and thus have four times the energy in storage and it would maintain the correct voltage for a good portion of that time.
However, the purpose of a capacitor across a Zener diode is to reduce Zener noise. This is a high frequency and low energy noise that would be amplified by Q1. Usually about 0.1uF is more than enough to eliminate such noise. It also would have no risk of destroying Q1 since it can't store that much energy. I'm assuming that is what the original intent of the circuit was since it a pretty basic low current series regulator.
In any case, its not to reduce hum, or bypass hum or any other nonsense. The use of a 4000uF capacitor would do nothing for hum removal (unless there was a design fault elsewhere and that should be addressed first) and would also do nothing for the removal of Zener noise as Zener noise is higher frequency and electrolytic capacitors (4000uF means electro) have poor high frequency response.
Do they get electronics engineers to check this stuff?
Because I really think they should.